A woman is heterozygous for a rare dominant autosomal genetic disease, Neurofibromatosis. She marries a normal man (homozygous recessive for
Question
A woman is heterozygous for a rare dominant autosomal genetic disease, Neurofibromatosis. She marries a normal man (homozygous recessive for Neurofibromatosis), who has Red-Green Color blindness, an X-linked recessive trait. They have children. If the woman is homozygous for normal vision, what is the chance they will have a daughter with color blindness?
A. 100%
B. 50%
C. 0%
D. 25%
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2022-02-13T04:39:21+00:00
2022-02-13T04:39:21+00:00 2 Answers
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Answer:
it would be D. 25%
Answer:
Option A
Explanation:
Given –
Man has X-linked recessive trait . Thus its genotype can be represented as
YX’
Woman has normal vision with homozygous genotype i.e “XX”
A cross is carried out between the above two parents thereby producing following offspring –
Y X’
X XY XX’
X XY XX’
Out of four offspring two are boy “XY” which do not have Red-Green Color blindness
While the two daughters “XX’ ” have Red-Green Color blindness
Thus, all the daughters produced have Red-Green Color blindness. Thus the chance of having a daughter with color blindness is 100 percent
Option A