A woman is heterozygous for a rare dominant autosomal genetic disease, Neurofibromatosis. She marries a normal man (homozygous recessive for

Question

A woman is heterozygous for a rare dominant autosomal genetic disease, Neurofibromatosis. She marries a normal man (homozygous recessive for Neurofibromatosis), who has Red-Green Color blindness, an X-linked recessive trait. They have children. If the woman is homozygous for normal vision, what is the chance they will have a daughter with color blindness?
A. 100%
B. 50%
C. 0%
D. 25%

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Adeline 3 months 2022-02-13T04:39:21+00:00 2 Answers 0 views 0

Answers ( )

    0
    2022-02-13T04:40:33+00:00

    Answer:

    it would be D. 25%

    0
    2022-02-13T04:41:17+00:00

    Answer:

    Option A

    Explanation:

    Given –

    Man has X-linked recessive trait . Thus its genotype can be represented as

    YX’

    Woman has normal vision with homozygous genotype i.e “XX”

    A cross is carried out between the above two parents thereby producing following offspring –

    Y X’

    X XY XX’

    X XY XX’

    Out of four offspring two are boy “XY” which do not have Red-Green Color blindness

    While the two daughters “XX’ ” have Red-Green Color blindness

    Thus, all the daughters produced have Red-Green Color blindness. Thus the chance of having a daughter with color blindness is 100 percent

    Option A

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45:5+15-5:5+20+17*12-15 = ? ( )