Hair texture in humans is an example of incomplete dominance. If a man with curly hair has children with a woman with straight hair, all the

Question

Hair texture in humans is an example of incomplete dominance. If a man with curly hair has children with a woman with straight hair, all the children has an intermediate texture that is wavy hair. What is the likely proportion of phenotypes in their children?

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Kaylee 3 months 2022-02-13T10:47:04+00:00 2 Answers 0 views 0

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    2022-02-13T10:48:33+00:00

    Answer:

    100% wavy haired

    Explanation:

    Let the allele for curly hair texture be represented by C and the allele for for straight hair texture be c.

    A man with curly hair will have the genotype CC.

    A woman with straight hair will have the genotype cc.

    Crossing the two in marriage:

    CC   x   cc

    Progeny: Cc, Cc, Cc and Cc.

    Recall that the hair texture gene exhibit incomplete dominance, meaning that heterozygous individuals have intermediate attribute – wavy hair.

    Hence, all the children will have wavy hair.

    0
    2022-02-13T10:48:45+00:00

    Answer:

    100% Wavy hair

    Explanation:

    The gene involved here codes for hair texture in humans. The alleles of the gene (straight, S and curly, s) exhibits incomplete dominance. Incomplete dominance is a genetic scenario whereby one allele does not completely mask the expression of the other allele, instead an intermediate phenotype that is heterozygous is formed.

    In this case, a man with curly hair (ss) marries a woman with straight hair (SS). The children from this cross will all possess a heterozygous genotype (Ss) and be phenotypically wavy-haired, since Incomplete dominance is exhibited by the gene. Therefore, 100% of the offsprings/children will have wavy hair phenotype.

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